### Home > PC > Chapter 8 > Lesson 8.2.4 > Problem8-130

8-130.

Solve for $k$. $e^{kx} = m^{x}$ (Note that e is the base of natural log and not a variable.)

Take the natural log of both sides and bring the exponents down in front.

$e^{kx} = m^{x}$
$\left(kx\right)\ln\left(e\right) = \left(x\right)\ln\left(m\right)$
$\left(kx\right) = \left(x\right)\ln\left(m\right)$
$\left(k\right) = \ln\left(m\right)$