CPM Homework Help : PC Problem 8-130

Solve for $k$ . $e^{kx} = m^{x}$ (Note that e is the base of natural log and not a variable.)

Hint:

Take the natural log of both sides and bring the exponents down in front.

Answer:

$e^{kx} = m^{x}$
$\left(kx\right)\ln\left(e\right) = \left(x\right)\ln\left(m\right)$
$\left(kx\right) = \left(x\right)\ln\left(m\right)$
$\left(k\right) = \ln\left(m\right)$