3^x = 81

5^x = 5⁻¹

log3^x = log7

(3²)^2x = (3³)^x−2

2⁻¹ = log₉(log₃x)

$\text{log}_{9}(\text{log}_{3}x)=\frac{1}{2}$

$9^{1/2}=\log_3x$

$\text{log}_{3}x = 3$

3³ = x

x − 3 = 0
Solve for x.

lnx − 2 = 0
Solve for x.