CPM Homework Help : PC3 Problem 10-53

Graph $\frac { y ^ { 2 } } { 36 } - \frac { x ^ { 2 } } { 25 }= 1$ by locating the vertices and sketching the asymptotes.

Hint:

This hyperbola will open vertically and is centered at $(0, 0)$ . To determine the locations of the vertices, let $x = 0$ .

Answer:

The slopes of the asymptotes are: $\pm \frac{\sqrt{36}}{\sqrt{25}}$