### Home > PC3 > Chapter 10 > Lesson 10.1.3 > Problem10-53

10-53.

Graph $\frac { y ^ { 2 } } { 36 } - \frac { x ^ { 2 } } { 25 }= 1$ by locating the vertices and sketching the asymptotes.

This hyperbola will open vertically and is centered at $(0, 0)$. To determine the locations of the vertices, let $x = 0$

The slopes of the asymptotes are: $\pm \frac{\sqrt{36}}{\sqrt{25}}$