### Home > PC3 > Chapter 10 > Lesson 10.1.3 > Problem10-60

10-60.

Graph the hyperbolas described by the equations below.

1. $\frac{(x-2)^2}{4}-\frac{(y+1)^2}{16}=1$

This hyperbola opens horizontally.

The center is at $(2, −1)$.

1. $(y − 4)^2 −\frac { ( x + 2 ) ^ { 2 } } { 9 }=1$

This hyperbola opens vertically and is centered at $(−2, 4)$.

The slopes of the asymptotes are $±1/3$.