### Home > PC3 > Chapter 10 > Lesson 10.1.4 > Problem10-91

10-91.

Given $f(x) =\frac { x + 1 } { x - 2 }$ and $f(x + 1) =\frac { 1 } { 2 }$, what is the value of $x$?

$f(x + 1) = \frac{x+1+1}{x+1-2} = \frac{1}{2}$

$\ \ \ \ \ \ \ \ \ \ \ \ \Rightarrow \frac{\textit{x} + 2}{\textit{x} - 1} = \frac{1}{2}$