CPM Homework Help : PC3 Problem 10-91

Given $f(x) =\frac { x + 1 } { x - 2 }$ and $f(x + 1) =\frac { 1 } { 2 }$ , what is the value of $x$ ?

Step:

$f(x + 1) = \frac{x+1+1}{x+1-2} = \frac{1}{2}$

$\ \ \ \ \ \ \ \ \ \ \ \ \Rightarrow \frac{\textit{x} + 2}{\textit{x} - 1} = \frac{1}{2}$