### Home > PC3 > Chapter 13 > Lesson 13.3.3 > Problem13-131

13-131.

Evaluate the following limits.

1. $\lim \limits _ { x \rightarrow 2 } \frac { 2 x ^ { 3 } - 8 x } { x ^ { 2 } + x - 6 }$

Try substituting in $x = 2$. What happens?

Completely factor both the numerator and denominator. Simplify. Substitute in $x = 2$.

1. $\lim \limits _ { x \rightarrow - \infty } \frac { 2 x ^ { 3 } - 8 x } { x ^ { 2 } + x - 6 }$

Since this is a limit at infinity, use the dominant terms.