$\text{Combine the }\sqrt{2}\text{s with the }\sqrt{2}\text{s and the }\sqrt{7}\text{s}\ \text{ with the }\sqrt{7}\text{s.}$

$3\sqrt{2}+7\sqrt{7}$

$\sqrt[3]{2}\text{ is different from }\sqrt{2}.$

Rewrite each term in simple radical form so that you can identify like terms.

$\sqrt{(4)(5)}+\sqrt{(9)(5)}$

$2\sqrt{5}+3\sqrt{5}$

$3\sqrt{4}\sqrt{3}-\sqrt{16}\sqrt{2}+\sqrt{9}\sqrt{3}+2\sqrt{4}\sqrt{2}$