### Home > PC3 > Chapter 3 > Lesson 3.1.4 > Problem3-55

3-55.

Michelle has the problem $(2x+3)^2-3(2x+3)-10=0$ and is thinking of expanding the $(2x+3)$ terms and then solving. Laura suggests that she let $a=2x+3$ then solve $a^2-3a-10=0$. Use Laura’s suggestion to solve for $a$ and then use your solutions to solve for the values of $x$.

Solve for the values of $a$ first.
Then substitute the values of $a$ into $a=2x+3$.
Finally, solve for $x$. You should get two answers.