$3x^{−1}y^{−1} – 2x^{−1} + 2y^{−1} = 1$  

1. What is the value of $y$ when $x = -1$?

   Step (a):

   $3(-1)^{-1}y^{-1}-2(-1)^{-1}+2y^{-1} = 1$

2. Solve the equation for $y$.

   Step (b):

   $\frac{3}{xy}-\frac{2}{x}+\frac{2}{y}=1$