CPM Homework Help : A2C Problem 13-78

For each of the following equations, identify the curve, write the equation in graphing form, and describe any of the following terms that apply: center, vertex or vertices, and asymptotes.

$x^{2} − 16y^{2} − 32^{y} = 160$
Answer (a):
$\frac{x^2}{16}-\frac{(y+1)^2}{9}=1$
$\text{Asymptotes: }y=\pm\frac{4}{3}x-1$
Center: $(0, −1)$
Vertices: $\left(± 4, − 1\right)$

$y^{2}− 2y + 3x = 5$
Hint (b):
$x=-\frac{1}{3}(y-1)^2+2$

$16 + 6x − x^{2} − y^{2} = 0$

Hint (c):
See part (a).