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4-42.

What multiplier will you use for something that is increasing by 1%?

9.015 gigatons

You can either calculate the begining amount for 2000 and let time = x or
you can let the beginning amount be the same as in 1998 and let time = x + 2.

C(x) = 8(1.01)(x + 2) or 8.16(1.01)x