### Home > A2C > Chapter Ch4 > Lesson 4.1.3 > Problem 4-42

4-42.

What multiplier will you use for something that is increasing by 1%?

9.015 gigatons

You can either calculate the begining amount for 2000 and let time = *x* or

you can let the beginning amount be the same as in 1998 and let time = *x* + 2.

*C*(*x*) = 8(1.01)^{(}^{x}^{ + 2)} or 8.16(1.01)^{x}