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4-77.

Substitute 1 for r in the sphere and cylinder equations.

V = 4π

$\textit{V}=\frac{4}{3}\pi$

$\textit{V}=4\pi + \frac{4}{3}\pi$

$\frac{16}{3}\pi \approx 16.755 m^3$

Remember that the radius is being cubed.

The radius will not double because of the r, r2, r3 relationship.

Now, see part (a).

$\textit{V}=16\pi + \frac{32}{3}\pi$

The tank will be 83.776m3.

Remember that the total is the combination of a sphere and a cylinder.

$\textit{V}=\frac{4}{3}\pi\textit{r}^{3}+4\pi\textit{r}^{2}$