### Home > A2C > Chapter 1 > Lesson 1.2.4 > Problem1-114

1-114.

Solve each equation below for $x$.

1. $10 − 2(2x + 1) = 4(x − 2)$

There is more than one way to solve this problem.

One way to start is by multiplying.

$10 − 2(2x + 1) = 4(x − 2)$
$10 − 4x − 2 = 4x − 8$

Simplify by adding $4x$ to each side.

$8 = 8x − 8$

Simplify again by adding $8$ to both sides.

$16 = 8x$

Divide both sides by $8$.

$x = 2$

1. $5 − (2x − 3) = −8 + 2x$

See part (a) and remember to distribute the negative.

$x = 4$