### Home > A2C > Chapter 10 > Lesson 10.1.1 > Problem10-11

10-11.

There are 6 ways to get a sum of 7, and 2 ways to get 11.

$P\text{(7\,or\,11)=\frac{8}{36}=\frac{2}{9}}$

$\frac{1}{9}$

$\frac{2}{3}$