CPM Homework Help : A2C Problem 11-28

Answer (a):

$\frac{_8C_3 \cdot _4C_0}{_{12}C_3 }=\frac{14}{55}$

Answer (b):

$\frac{_8C_2 \cdot _4C_1}{_{12}C_3 }=\frac{28}{55}$

Hint (c):

See parts (a) and (b).

Hint (d):

See parts (a) and (b).

Hint (e):

How can you solve part (d) using combinations? How can you solve part (d) using the answers to parts (a) through (c)?