### Home > A2C > Chapter 11 > Lesson 11.1.2 > Problem11-28

11-28.

$\frac{_8C_3 \cdot _4C_0}{_{12}C_3 }=\frac{14}{55}$

$\frac{_8C_2 \cdot _4C_1}{_{12}C_3 }=\frac{28}{55}$

See parts (a) and (b).

See parts (a) and (b).

How can you solve part (d) using combinations? How can you solve part (d) using the answers to parts (a) through (c)?