### Home > A2C > Chapter 11 > Lesson 11.2.4 > Problem11-93

11-93.

Using your answers to the previous problem:

1. Factor $f\left(x\right) = x^{3} − 5x^{2} + 11x − 15$.

2. Solve $f\left(x\right) = 0.$

Use a generic rectangle to see if x − 3 is a factor.

$x^{2} − 2x + 5$

$\left(x − 3\right)\left(x^{2} − 2x + 5\right)$

Use the factors to solve for $x$.

$\left(x − 3\right)\left(x^{2} − 2x + 5\right)$

$x = 3$

Use the quadratic formula to solve the other factor.

$x=\frac{2\pm\sqrt{4-20}}{2}$

$x = 1 ± 2i$

$x = {3, 1 ± 2i}$