### Home > A2C > Chapter 11 > Lesson 11.3.2 > Problem 11-150

11-150.

10 log(2) ≈ 3.0

*P* = 20 · 10^{6} = 2 · 10^{7}

The sound ratio is 1.

100 times more pressure.

11-150.

10 log(2) ≈ 3.0

*P* = 20 · 10^{6} = 2 · 10^{7}

The sound ratio is 1.

100 times more pressure.