### Home > A2C > Chapter 12 > Lesson 12.1.1 > Problem12-9

12-9.

Change the relation below into graphing form, find the locator point (h, k), and sketch a graph of the relation.

$x = 2y^{2} − 12y + 13$

Complete the square of $y$.

$x = 2\left(y^{2} − 6y\right) + 13$

$x = 2\left(y^{2} − 6y + 9\right) − 18 + 13\\x = 2\left(y − 3\right)^{3} − 5$

Locator point: $\left(−5, 3\right)$