CPM Homework Help : A2C Problem 12-39

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Home > A2C > Chapter 12 > Lesson 12.1.2 > Problem 12-39

12-39.

Solve.

$5^{x−3} = 120$
Hint (a):
Use the properties of logarithms.
Answer (a):
log(5^x^{− 3}) = log(120)
(x − 3)(log5) = log120
$x-3=\frac{\text{log}120}{\text{log}5}$
$x=3+\frac{\text{log}120}{\text{log}5}\approx5.97$

$log\left(2x + 1\right) = −1$
Answer (b):
$-\frac{9}{20}$

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