CPM Homework Help : A2C Problem 12-127

For each equation below, identify the curve, write the equation in graphing form, state the locator point, and draw the graph.

$12x^{2} + 8y^{2} + 48x − 48y + 24 = 0$
Hint (a):
$12\left(x^{2} + 4x\right) + 8\left(y^{2} − 6y\right) = −24$
$12\left(x^{2} + 4x + 4\right) + 8\left(y^{2} − 6y + 9\right) = −24 + 12\left(4\right) + 8\left(9\right)$
$\frac{(x+2)^2}{8}+\frac{(y-3)^2}{12}=1$