Challenge: Use the general form for the Binomial Theorem to show that the sum of the elements of the n^th row of Pascal's Triangle is $2^{n}$ .

_{$\large{_{n}C_{n} + _{n}C_{n−1}+ _{n}C_{n2} + …+ _{n}C_{2} + _{n}C_{1} + _{n}C_{0} = 2^{n}}$}