### Home > A2C > Chapter 13 > Lesson 13.1.1 > Problem13-13

13-13.

Set one of the variables so that its squared quantity is zero, then solve for the other.

$\frac{((2)-2)^2}{16}+\frac{(y-3)^2}{25}=1$

(0) + (y − 3)3 = 25
y = 3 ± 5