### Home > A2C > Chapter 13 > Lesson 13.1.1 > Problem13-13

13-13.

Graph = $\frac { ( x - 2 ) ^ { 2 } } { 16 } + \frac { ( y - 3 ) ^ { 2 } } { 25 } = 1$.

1. What are the coordinates of the four relocated intercepts? These points, at the top, bottom, left, and right extremes of the ellipse, are called the vertices of the ellipse.

Set one of the variables so that its squared quantity is zero, then solve for the other.

$\frac{((2)-2)^2}{16}+\frac{(y-3)^2}{25}=1$

$\left(0\right) + \left(y − 3\right)^{3} = 25\\y = 3 ± 5$

2. Choose two of the four points you found in part (a) and substitute their coordinates into the equation to show that they check.