CPM Homework Help : A2C Problem 13-71

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Home > A2C > Chapter 13 > Lesson 13.1.4 > Problem 13-71

13-71.

Solve each equation below for $x$ if $-2π ≤ x ≤ 2π.$

$4\sin^2(x)=1$
Step 1(a):
$\sin^2(x)\ =\frac{1}{4}$
Divide both sides by $4$ .
Step 2(a):
Take the square root of both sides to solve for sin $(x)$ .
$\sin(x)\ =±\frac{1}{2}$
Step 3(a):
Find the corresponding angles on the unit circle.
Answer (a):

$3\tan^2(x)=1$
Hint (b):
Follow the steps in part (a).

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