### Home > A2C > Chapter 13 > Lesson 13.1.4 > Problem13-77

13-77.

Find the equation of a cubic function that has $y = x^{3}$ as its parent graph, a locator point at $\left(−6, −10\right)$, and passes through the origin.

Write a general equation based on the locator point:

$y = a\left(x + 6\right)^{3} − 10$

Substitute (0, 0) for x and y and solve for a.

$\left(0\right) = a\left(\left(0\right) + 6\right)^{3} − 10$

$y=\frac{10}{216}(x+6)^3-10$