### Home > A2C > Chapter 13 > Lesson 13.2.1 > Problem 13-97

13-97.

Solve for

*x*in*degrees*. Homework Help ✎2sin(

*x*) = 1cos

^{2}(*x*) + 4cos(*x*) + 4 = 0

Draw a 30°-60°-90° triangle and label the sides.

In the first quadrant, the side opposite the 30° is one-half.

In the second quadrant, the angle with sine equal to one-half is 180° − 30° or 150°.

*x* = 30° + 360°*n* or *x* = 150° + 360°*n*

Factor the equation and simplify.

There is no solution.