CPM Homework Help : A2C Problem 13-116

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Home > A2C > Chapter 13 > Lesson 13.2.2 > Problem 13-116

13-116.

Solve.

$\operatorname{log}_{7}\left(3x − 2\right) = 2$
Hint (a):
$3x − 2 = 7^{2}$

$2^{x} − 2^{x−2} − 16^{2} = 0$
Hint (b):
$16 = 2^{4}$
Answer (b):
$x = 5$

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