CPM Homework Help : A2C Problem 5-27

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Home > A2C > Chapter 5 > Lesson 5.1.2 > Problem 5-27

5-27.

Solve each of the following equations using any method.

$2\left(x + 3\right)^{2} − 5 = −5$
Step 1(a):
$2\left(x + 3\right)^{2} = 0$
Step 2(a):
$\left(x + 3\right)^{2} = 0$
Answer (a):
$x = −3$

$3\left(x −2\right)^{2} + 6 = 9$
Hint (b):
See part (a).

$| 2 x - 5 | - 6 = 15$
Step 1(c):
$\mid 2\textit{x} - 5 \mid = 21$
Step 2(c):
$2x − 5 = ± 21$
Answer (c):
$x = −8 \text{ or } x = 13$

$3 \sqrt { 5 x - 2 }+ 1 = 7$

Hint (d):

$\sqrt{5\textit{x}-2} = 2$

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