CPM Homework Help : A2C Problem 6-49

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Home > A2C > Chapter 6 > Lesson 6.1.3 > Problem 6-49

6-49.

Solve each of the following equations.

$\frac { 3 x } { 5 } = \frac { x - 2 } { 4 }$
Answer (a):
$\textit{x}=-\frac{10}{7}$

$\frac { 4 x - 1 } { x } = 3 x$
Hint (b):
$4x − 1 = 3x^{2}$
$3x^{2} − 4x + 1 = 0$

$\frac { 2 x } { 5 } - \frac { 1 } { 3 } = \frac { 137 } { 3 }$
Answer (c):
$x = 115$

$\frac { 4 x - 1 } { x + 1 } = x - 1$
Hint (d):
Use the same method as in part (b).

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