### Home > A2C > Chapter 7 > Lesson 7.1.3 > Problem 7-42

7-42.

Solve for *x*, *y*, and *z*: (2* ^{x}*)(3

*)(5*

^{y}*) = (2*

^{z}^{3})(3

^{x}^{−2})(5

^{2}

^{x}^{−3}

*). Homework Help ✎*

^{y}Make a system of equations using the exponents.

*x* = 3*y* = *x* − 2*z* = 2*x* − 3*y*

The system of equations gives you the value of *x*. Substitute the value of *x* into the second and third equations.

From there, solve as if there were only two equations.