CPM Homework Help : A2C Problem 7-120

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Home > A2C > Chapter 7 > Lesson 7.2.2 > Problem 7-120

7-120.

Solve each of the following equations.

$\frac { x } { 3 } = x + 4$
Step (a):
Remove the fraction:
$x = 3x + 12$ .
Answer (a):
$−6$

$\frac { x + 6 } { 3 } = x$

$\frac { x + 6 } { x } = x$
Answer (c):
$−2, 3$

$\frac { 2 x + 3 } { 6 } + \frac { 1 } { 2 } = \frac { x } { 2 }$

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