CPM Homework Help : A2C Problem 9-14

CPM Homework Banner

Home > A2C > Chapter 9 > Lesson 9.1.1 > Problem 9-14

9-14.

Solve the equations below.

$\frac { 3 x } { x + 2 } + \frac { 7 } { x - 2 } = 3$
Hint (a):
Multiply both sides by $(x + 2)(x - 2)$ .
Step (a):
$3x(x - 2) + 7(x + 2) = 3(x + 2)(x - 2)$
$3x^² - 6x + 7x + 14 = 3(x^2 - 4)$
$3x^2 + x + 14 = 3x^2 - 12$
Answer (a):
$x = -26$

$\frac { x - 7 } { x - 5 } = \frac { 6 } { x }$
Answer (b):
$x = 10, x = 3$

© 2022 CPM Educational Program. All rights reserved.