Consider the function $y = x^{2} + 5x + 7$.

1. Complete the square to find the vertex.

   Answer (a):

   $\text{Vertex: }\left(-\frac{5}{2},\,\frac{3}{4}\right)$

2. Find the y-intercept.

   Answer (b):

   (0, 7)

3. Use the vertex, the y-intercept, and the symmetry of parabolas to find a third point and sketch the graph.

   Show Graph (c):