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Home > A2C > Chapter 9 > Lesson 9.3.1 > Problem 9-121

9-121.

x = −7

y = −343 + 245 + 112 −14
y = 0

(x + 7)

Divide x3 + 5x2 −16x −14 by x + 7 using a generic rectangle.

x2 −2x −2

x 3 + 5x 2 − 16x − 14 = (x + 7)(x 2 − 2x − 2) = 0

Try using the quadratic formula.