Home > A2C > Chapter 9 > Lesson 9.3.1 > Problem 9-121
9-121.
x = −7
y = −343 + 245 + 112 −14
y = 0
(x + 7)
Divide x3 + 5x2 −16x −14 by x + 7 using a generic rectangle.
x2 −2x −2
x 3 + 5x 2 − 16x − 14 = (x + 7)(x 2 − 2x − 2) = 0
Try using the quadratic formula.