
Home > A2C > Chapter 9 > Lesson 9.3.2 > Problem 9-146
9-146.
Substitute y + z for x into the second equaton.
2y + 2z + 3y + z = 17
3z + 5y = 17
Multiply the third equation by −3 then add it to the earlier equation.
3z + 5y = 17
−3z − 6y = −21
−y = −4
Substitute 4 for y.
z + 8 = 7
Substitute 4 and −1 for y and z.
x = 4 − 1
y = 4
z = −1
x = 3
(3, 4, −1)