### Home > A2C > Chapter 9 > Lesson 9.3.2 > Problem9-153

9-153.

1. $\sqrt { x } + 2 = x$

Square both sides.

Set the equation equal to $0$.

Factor the equation.

$\sqrt{\textit{x}}=\textit{x}-2$

$x = x^{2} − 4x + 4$

$x^{2} − 5x + 4 = 0$

$\left(x − 4\right)\left(x − 1\right)$

$x = 4$

1. $\sqrt { x } + 2 = \sqrt { x + 6 }$

• You will need to square twice.