### Home > AC > Chapter 11 > Lesson 11.1.3 > Problem11-35

11-35.

Solve for x. Use any method. Check your solutions by testing them in the original equation.

1. $| x - 3 | = 5$

$x = 8 \text{ or } x = −2$

1. $5 | x | = 35$

Divide by $5$, then solve.

$x = ±7$

1. $| x + 1 | = 2$

Use the same method as part (a).

$x = 1 \text{ or } −3$

1. $| x + 3 | - 6 = - 4$

Can an absolute value equal a negative number?