### Home > AC > Chapter 11 > Lesson 11.3.1 > Problem 11-102

11-102.

Find the equation of the line perpendicular to 5*x* − 2*y* = 13 that passes through the point (60, −20). Homework Help ✎

Solve for *y* so the equation is in *y* = m*x* + b form. m = slope (growth)

Subtract 5*x* from both sides.

−2*y* = −5*x* + 13

Divide both sides by −2.

The line perpendicular to the line in the problem has a slope that is the negative reciprocal of the slope of line.

b = 130