CPM Homework Help : AC Problem 12-46

How much coffee costing $$6$ per pound should be mixed with $3$ pounds of coffee costing $$4$ per pound to create a mixture costing $$4.75$ per pound?

Step:

Three pounds of $$4/\text{lb}$ coffee is worth $$12$ . Let $x=\text{ the number of pounds of }\$6/\text{lb coffee}$ .
Then $6x =\text{ the cost of that much coffee}$ . Put the total cost of the coffee (DOLLARS) over (PER) the total number of pounds (POUND) equal to $$4.75$ per pound.
Then solve for $x$ .

$\frac{\left(12+6\textit{x}\right)}{3+\textit{x}}=4.75$