Substitute 7 into the equation.

$g(7) = \sqrt{7 - 3} + 1$

$g(7) = \sqrt{4} + 1$

$g\left(7\right) = 2 + 1$

$g\left(7\right) = 3$

$g(4) = 2$

Can you take the square root of a negative number?