$f ( 6 ) = \frac { 6 ^ { 2 } } { 6 + 5 }$

$f ( 6 ) = \frac { 36 } { 11 }$

$g ( 17 ) = \sqrt { 3 ( 17 ) - 2 }$

$\left. \begin{array} { l } { g ( 17 ) = \sqrt { 51 - 2 } } \\ { g ( 17 ) = \sqrt { 49 } } \end{array} \right.$

$g(17)=7$

$f(−5)=$ undefined

Substitute $-1$ into the equation $g\left(x\right)$ and $2$ into the equation $f\left(x\right)$.

Subtract the second answer from the first.

$g\left(x+2\right)=\sqrt{3x+4}$