t(n) = 3n

$\textit{t}(\textit{n})=-20\left(\frac{1}{2}\right)^{\textit{n}-5}\text{ or }\textit{t}(\textit{n})=-640\left(\frac{1}{2}\right)^\textit{n}$

$\textit{t}(\textit{n})=12(3)^{\textit{n}-4}\text{ or }\textit{t}(\textit{n})=\frac{4}{27}(3)^\textit{n}$

t(n) = −3n + 10

See part (c).

See part (e).