### Home > AC > Chapter 16 > Lesson 16.9.2.1 > Problem9-68

9-68.

3x = 81

5x = 5−1

log3x = log7

(32)2x = (33)x−2

2−1 = log9(log3x)

$\text{log}_{9}(\text{log}_{3}x)=\frac{1}{2}$

$9^{1/2}=\log_3x$

$\text{log}_{3}x = 3$

33 = x

x − 3 = 0
Solve for x.

lnx − 2 = 0
Solve for x.