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2-103.

At the annual dog show, Chantel noticed that there were three more Schnauzers than Scotties. She also realized that the number of Wirehaired Terriers was five less than twice the number of Schnauzers. If there were $78$ dogs in all (counting Schnauzers, Scotties, and Wirehaired Terriers), how many Schnauzers were there?

Make a guess and check table with the first column labeled Schnauzers, the second column labeled Scotties (Schnauzers $−3$), the third column labeled Terriers ((Schnauzers$(2)−3$), and the fourth column labeled Total $=78$.

Schnauzers

Scotties

Terriers

Total

$x$

$x-3$

$2x-3$

$78$

Using your table, write algebraic expressions for the number of each dog. Using that information, write an equation and solve.