### Home > AC > Chapter 5 > Lesson 5.1.2 > Problem5-17

5-17.

When solving $\frac{x}{6}=\frac{5}{2}$ for $x$, Nathan noticed that $x$ is divided by $6$.

1. What can he do to both sides of the equation to get $x$ alone?

Undo the division by multiplying by $6$.

2. Solve for $x$. Then check your solution in the original equation.

$\frac{\textit{x}}{6}=\frac{5}{2}$

$\frac{x}{6}\cdot6=\frac{5}{2}\cdot6$

$\frac{6x}{6}=\frac{30}{2}$

$x=15$

CHECK

$\frac{x}{6}=\frac{5}{2}$

If $x=15$:

$\frac{15}{6}=\frac{5}{2}$

$15=\frac{5}{2}\cdot6$

$2\cdot15=30$

$30=30$

3. Use the same process to solve this equation for $x$: $\frac{x}{10}=\ \frac{2}{5}$.

• $x=4$