### Home > AC > Chapter 6 > Lesson 6.1.3 > Problem6-27

6-27.

Nina has some nickels and $9$ pennies in her pocket. Her friend, Maurice, has twice as many nickels as Nina. Together, these coins are worth $84¢$. How many nickels does Nina have? Solve using any method, but show all of your work.

Let $n$ represent the number of nickles

$5n+9=$ Nina's money (nickles are worth $5$ cents so multiply $n$ by $5$).
$2(5n)=$ Maurice's money.

Set up an equation. Nina's money $+$ Maurice's money $=84$ cents. So, $5n+9+10n=84$

Nina has five nickels.