### Home > AC > Chapter 6 > Lesson 6.3.1 > Problem6-107

6-107.

Solve the following equations for $x$, if possible. Check your solutions.

1. $−(2 − 3x) + x = 9 − x$

1. $\frac { 6 } { x + 2 } = \frac { 3 } { 4 }$

1. $5 − 2(x + 6) = 14$

1. $\frac{1}{2}x-4+1=-3-\frac{1}{2}x$

To solve for x you need to isolate the variable, or get it alone.

Distribute
−2 + 3x + x = 9 − x
Add like terms
4x − 2 = 9 − x
Isolate variable by adding 2 and an x to both sides.
5x = 11
Divide
x = 2.2
Check your answer in the original equation.

Multiply by a common denominator to remove fractions.

Use the same method as seen in part (a) to solve part (b).

x = 6

Use the same methods as parts (a) and (b) to solve parts (c) and (d).

x = −10.5