### Home > AC > Chapter 7 > Lesson 7.2.3 > Problem7-73

7-73.

Find the point of intersection of the lines $3=6x-y$ and $3x-2y=24$.

One strategy to solve this problem is to solve it as a system of equations.
$\begin{array}{l} 3x − 2y = 24 \\ 6x − y = 3 \end{array}$

Multiply the bottom equation by $-2$ to cancel out the $y\text{'s}$.

$\begin{array}{r} 3x − 2y = 24 \;\\ −12x + 2y = -6 \\ -9x \qquad \;= 18 \; \end{array}$

Solve for $x$, then substitute the value back into one of the original equations to solve for $y$.