### Home > AC > Chapter 7 > Lesson 7.3.1 > Problem7-88

7-88.

Solve each of the following equations for $x$.

1. $\frac{x}{6}=\frac{7}{3}$

Multiply both sides by $18$.

$(18)\frac{x}{6}=\frac{7}{3}(18)$

$3x = 42$

Divide both sides by $3$.

$x = 14$

Don't forget to check your solution!

1. $3x+2=7x-8$

Subtract $3x$ from both sides.

\begin{aligned}[t] 3x + 2 &= 7x - 8 \\ -3x &= -3x \\ \hline 2 &= 4x - 8 \end{aligned}

Add $8$ to both sides.

\begin{aligned}[t] 2 &= 4x - 8 \\ + 8 &= \quad \; \, +8 \\ \hline 10 &= 4x \end{aligned}

Divide by $4$.

$x=\frac{10}{4}=\frac{5}{2}=2.5$

1. $\frac{6}{x}=\frac{4}{x+1}$
1. $6(x-4)=42$
Divide both sides by $6$.