### Home > AC > Chapter 7 > Lesson 7.3.3 > Problem7-107

7-107.

Find the point of intersection of the system of linear equations below.

\begin{aligned}[t] 8 - 3x = y \\ 2y + 3x = 5 \end{aligned}

Rearrange the top equation so that it matches the form of the bottom equation.
\begin{aligned}[t] -y - 3x &= -8 \\ 2y + 3x &= 5 \end{aligned}

Solve the system of equations by eliminating the $x\text{'s}$.
$y=-3$

Now substitute the value for $y$ back into one of the original equations to solve for $x$.

$\left(\frac{11}{3},-3\right)$