### Home > AC > Chapter 7 > Lesson 7.3.4 > Problem7-114

7-114.

Find the equation of each line below.

1. The line with slope $m=-\frac{2}{3}$ that goes through the point $\left(−6, 5\right)$.

Using $y = mx + b$, substitute the values of $m, y,$ and $x$ and solve for $b$.

$5=-\frac{2}{3}(-6)+b$

Solve for $b$ and rewrite the equation substituting $m$ and $b$ back into their original positions.

2. A horizontal line that goes through the point $\left(8, −11\right)$.

A horizontal line has zero slope. Therefore, simply substitute the values for $x$ and $y$ into the equation and solve for $b$.
Then, rewrite the equation with $m$ and $b$ substituted back into their original equations.

$y = −11$

3. The line perpendicular to the line in part (a) above but going through the origin.

See parts (a) and (b) to solve. Remember that perpendicular lines have opposite reciprocal slopes.